: Comprehensive formulas for the path of a projectile (parabolic trajectory), Time of Flight ( ), Maximum Height ( ), and Horizontal Range ( Vector Addition
If you want a for Class 11, you might need to create it yourself or find a creative blog. Search for:
By mastering these derivations, you build a solid foundation for Class 12 and future competitive exams.
: Proof of the conservation of energy for flowing fluids.
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Class 11 Physics is a crucial foundation for understanding the principles of physics, and derivations play a significant role in grasping these concepts. Here are some of the most important derivations in Class 11 Physics:
Always draw clear, labeled diagrams. They often carry marks and help in visualizing the steps.
Derive that work done by all forces equals the change in kinetic energy.
Pascal’s law and hydrostatic pressure. Terminal Velocity: Stokes’ law application. Bernoulli’s Equation: Excess Pressure: Inside a liquid drop and a bubble. 7. Thermodynamics Work Done in Isothermal Process: Work Done in Adiabatic Process: Efficiency of Carnot Engine: 8. Oscillations and Waves Simple Harmonic Motion (SHM): Expression for time period ( Energy in SHM: Total energy of a particle executing SHM. Speed of Transverse Wave on a String: 💡 How to Download the "All Important Derivations" PDF : Comprehensive formulas for the path of a
43πr3ρg=43πr3σg+6πηrvfour-thirds pi r cubed rho g equals four-thirds pi r cubed sigma g plus 6 pi eta r v
2πrTcosθ=πr2hρg2 pi r cap T cosine theta equals pi r squared h rho g 2Tcosθ=rhρg2 cap T cosine theta equals r h rho g
12mve2=GMmR⟹ve=2GMR=2gRone-half m v sub e squared equals the fraction with numerator cap G cap M m and denominator cap R end-fraction ⟹ v sub e equals the square root of the fraction with numerator 2 cap G cap M and denominator cap R end-fraction end-root equals the square root of 2 g cap R end-root Unit 6: Properties of Bulk Matter
Escape velocity is the minimum speed required for an object to escape a planet's gravitational pull permanently. The gravitational force on an object of mass at a distance from the center of the Earth is: This public link is valid for 7 days
τ=−mgl(xl)=−mgxtau equals negative m g l open paren x over l end-fraction close paren equals negative m g x We also know . Equating the two expressions:
: Using Stokes’ Law to find the constant velocity of a sphere in a viscous fluid.
Fup=T⋅2πr⋅cosθ(where θ=contact angle)cap F sub u p end-sub equals cap T center dot 2 pi r center dot cosine theta space open paren where theta equals contact angle close paren The downward force is the weight of the liquid column:
∫0sa⋅ds=∫uvv⋅dvintegral from 0 to s of a center dot d s equals integral from u to v of v center dot d v
ΔK=12Δm(v22−v12)cap delta cap K equals one-half delta m open paren v sub 2 squared minus v sub 1 squared close paren
dKdt=F⋅dxdtthe fraction with numerator d cap K and denominator d t end-fraction equals cap F center dot d x over d t end-fraction dK=F⋅dxd cap K equals cap F center dot d x Integrate both sides from the initial state (position , kinetic energy Kicap K sub i ) to the final state (position , kinetic energy Kfcap K sub f
